Image Credit: Pixabay.com
We all know that each 100% vote costs your 2% voting power, and every 24 hours, your voting power restores 20%. This means that you can vote 10 times at 100% one day and the voting power will remain the same the next day.
The question comes: Given a 30 days period, and approximately 60% voting power at the day 1, is there a much bigger gain to restore your voting power to 100% (wait 2 days) ?
I always thought there is not much difference in terms of total curation earnings until today.. I wrote a VBScript that reveals the truth.
The first strategy, just vote 10 times 100% per day every day in the 30 days' period. Assume 10K SP 100% gives 1 SBD. And suppose the 10 votes are done in a row (the VP restored during upvotes can be ignored)
Function Strategy1(ByVal sp, ByVal vp, ByVal days)
income = 0
While days > 0
For i = 1 To 10
income = income + sp * vp / 10000
vp = vp - 0.02
Next
vp = vp + 0.2
days = days - 1
Wend
Strategy1 = income
End Function
The second strategy, let's wait a few days before the VP is restored, adding a parameter rest in the unit of days.
Function Strategy2(ByVal sp, ByVal vp, ByVal days, ByVal rest)
days = days - rest
vp = vp + 0.2 * rest ' 1 day restores 20%
If vp > 1 Then
vp = 1 ' voting power can only be maximum 100%
End If
income = 0
While days > 0
For i = 1 To 10
income = income + sp * vp / 10000
vp = vp - 0.02
Next
vp = vp + 0.2
days = days - 1
Wend
Strategy2 = income
End Function
In my case, I have 10K SP so let's assume these values:
steempower = 10000
votingpower = 0.6
daysofcuration = 30
restoredays = 2
So the simulation gives:
WScript.Echo ("Strategy 1 Max Income = " & Strategy1(steempower, votingpower, daysofcuration))
WScript.Echo ("Strategy 2 Max Income = " & Strategy2(steempower, votingpower, daysofcuration, restoredays))
Strategy 1 Max Income = 152.999999999999
Strategy 2 Max Income = 254.799999999999
This is a BIGGGGGGGGG difference! The lower voting power, longer periods, the bigger difference! So.... you might consider letting your upvoting robot take a few days' rest...
Correction @tumutanzi told me my understanding was not exactly right. The 2% loss is to the current VP, so instead of vp = vp - 0.02 the correct version is vp = vp * 0.98.
So the correct version to emulate steemit curator is (you can vote 11 times per day)
Function Strategy1(ByVal sp, ByVal vp, ByVal days)
income = 0
While days > 0
For i = 1 To 11
income = income + sp * vp / 10000
vp = vp * 0.98
Next
vp = vp + 0.2
If (vp > 1) Then
vp = 1
End If
days = days - 1
Wend
Strategy1 = income
End Function
Function Strategy2(ByVal sp, ByVal vp, ByVal days, ByVal rest)
days = days - rest
vp = vp + 0.2 * rest
If vp > 1 Then
vp = 1
End If
income = 0
While days > 0
For i = 1 To 11
income = income + sp * vp / 10000
vp = vp * 0.98
Next
vp = vp + 0.2
If (vp > 1) Then
vp = 1
End If
days = days - 1
Wend
Strategy2 = income
End Function
And this gives totally different results,
steempower = 10000
votingpower = 0.6
daysofcuration = 30
restoredays = 2
WScript.Echo ("Strategy 1 Max Income = " & Strategy1(steempower, votingpower, daysofcuration))
WScript.Echo ("Strategy 2 Max Income = " & Strategy2(steempower, votingpower, daysofcuration, restoredays))
It indicates there is NOT much difference at all!
Strategy 1 Max Income = 279.67590316366
Strategy 2 Max Income = 278.976108950286
Image Credit: Pixabay.com
虽然说小鱼的点赞策略就是喜欢的点，因为SP少点赞收益没有多少区别，但是现在 @justyy 已经有超过1万的SP 了，所以今天想了一下这么一个问题。
我们都知道，一次100%点赞消耗能量 2%，一天恢复20%的能量相当于一天中你可以点满10次。那么问题就是，假设30天时间内，你一天点10次，最大收益是多少？
为了简化分析模型，我们假设1万SP能量全满点赞收益是1 SBD，那么如果初始能量只有60%，我们是不是需要等恢复了90%甚至是全满后再点这样效果会好一点呢？
我本来以为没啥区别，直到今天晚上无聊随便写了段VBScript代码来分析，结果让我很吃惊。
第一种策略，从第一天就开始点满10次，假设这10次都是一下子点完，两次点赞间的能量恢复可以忽略不计，那么我们可以用以下代码来模拟：
Function Strategy1(ByVal sp, ByVal vp, ByVal days)
income = 0
While days > 0
For i = 1 To 10
income = income + sp * vp / 10000
vp = vp - 0.02
Next
vp = vp + 0.2
days = days - 1
Wend
Strategy1 = income
End Function
第二种策略，多加了一个参数，先休息几天，恢复恢复能量，然后再点。
Function Strategy2(ByVal sp, ByVal vp, ByVal days, ByVal rest)
days = days - rest
vp = vp + 0.2 * rest ' 每天恢复20%
If vp > 1 Then
vp = 1 ' 能量最多恢复到100%
End If
income = 0
While days > 0
For i = 1 To 10
income = income + sp * vp / 10000
vp = vp - 0.02
Next
vp = vp + 0.2
days = days - 1
Wend
Strategy2 = income
End Function
我有1万SP，那么假定这些值。
steempower = 10000
votingpower = 0.6
daysofcuration = 30
restoredays = 2
跑一下程序看看结果：
WScript.Echo ("Strategy 1 Max Income = " & Strategy1(steempower, votingpower, daysofcuration))
WScript.Echo ("Strategy 2 Max Income = " & Strategy2(steempower, votingpower, daysofcuration, restoredays))
Strategy 1 Max Income = 152.999999999999
Strategy 2 Max Income = 254.799999999999
太意外了，你的VP越低，统计时间越长，效果差别就越大，OMG，还是先让机器人缓几天吧，至少点赞比率先降一降，等恢复了差不多了这样每天保持10次点赞 点完能量保持在80%左右，这样是最优的。
错啦错啦 @tumutanzi 告诉我，我的理解有问题， 2%的损失不是 vp = vp - 0.02 而是针对当前VP能量，所以应该是vp = vp * 0.98.
程序更正一下，每天可以点11次，点10次能量满的话就会浪费：
Function Strategy1(ByVal sp, ByVal vp, ByVal days)
income = 0
While days > 0
For i = 1 To 11
income = income + sp * vp / 10000
vp = vp * 0.98
Next
vp = vp + 0.2
If (vp > 1) Then
vp = 1
End If
days = days - 1
Wend
Strategy1 = income
End Function
Function Strategy2(ByVal sp, ByVal vp, ByVal days, ByVal rest)
days = days - rest
vp = vp + 0.2 * rest
If vp > 1 Then
vp = 1
End If
income = 0
While days > 0
For i = 1 To 11
income = income + sp * vp / 10000
vp = vp * 0.98
Next
vp = vp + 0.2
If (vp > 1) Then
vp = 1
End If
days = days - 1
Wend
Strategy2 = income
End Function
假定以下值：
steempower = 10000
votingpower = 0.6
daysofcuration = 30
restoredays = 2
WScript.Echo ("Strategy 1 Max Income = " & Strategy1(steempower, votingpower, daysofcuration))
WScript.Echo ("Strategy 2 Max Income = " & Strategy2(steempower, votingpower, daysofcuration, restoredays))
这结果显示，没啥区别，不得不说，这系统设计的真巧妙。是我没弄清楚，丢人了（捂脸）
Strategy 1 Max Income = 279.67590316366
Strategy 2 Max Income = 278.976108950286
@justyy 是 https://justyy.com 的博主，在 @tumutanzi 大哥 的介绍下加入 STEEMIT，写些帖子挣些小钱养家糊口。
@justyy 也是CN 区的点赞机器人，对优质内容点赞，只要代理给 @justyy 每天收利息（年化率14.6%）并能获得一次至少2倍(VP 200%+)的点赞，大鱼 @htliao 都加入了这个计划(530 SP)表示支持。
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