#chemistrychallenge 3


Once more I ( @jaki01 ) let my #chemistrychallenge run under the SteemSTEM flag to support this still growing science community which in my eyes adds a lot of value to our Steemit community!

What could be more fun than activating your brain and at the same time having the opportunity to win up to 15 STEEM. :-)

Rules - what are the requirements to win the prize?

The winner is the first person to post the correct solution (correct number and correct unit; solution process required). The prize for the correct answer is 15 STEEM. We will send it to the winner immediately after the article is paid out (7 days after posting).

If nobody is able to determine the solution before Sunday, May 14th, 2017 at 10 pm (German time!) the prize (15 STEEM) will be added to the next competition (bringing that one up to 30 STEEM!).

Liquid fluorine:

                                                              Source: Par Fulvio314


Your Chemistry Challenge to Solve:


Fluorine can segregate into atoms according to the equation

F2      ------->      2 F        ∆H = + 158 kJ

That means the energy one needs to split 1 mole F2 amounts to 158 kJ (kilojoule).

Question:

What color would have a photon, which had exactly the energy necessary to segregate one single F2 molecule into two F atoms?

Some (possibly, some may be to trick you) Useful Constants:


  • Speed of light: c = 3.0 x 108 m/s (meters / second)
  • Planck constant: h = 4.136 x 10-15 eV∙s (electron volt ∙ second)
  • Faraday constant: F = 9.65 x 104 C/mol (coulomb / mol)
  • Avogadro constant: NA = 6.022 x 1023 mol-1 (atoms / mol)
  • jaki01's constant: j = 6.488 x 1016 awesomes / science

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